Question
Calculate the $\mathrm{pH}$ of a $0.050 \mathrm{M} \mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}$ solution. The $K_{\mathrm{a}}$ value for $\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}$ is $1.4 \times 10^{-5}$.
Step 1
Aluminum nitrate, \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\), dissociates in water to form \(\mathrm{Al}^{3+}\) ions and \(\mathrm{NO}_{3}^{-}\) ions. The \(\mathrm{Al}^{3+}\) ion can hydrolyze in water to form Show more…
Show all steps
Your feedback will help us improve your experience
Bin Chen and 75 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Calculate the $\mathrm{pH}$ of a $0.050 \mathrm{M} \mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}$ solution. The $K_{\mathrm{a}}$ value for $\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}$ is $1.4 \times 10^{-5}$
Calculate the $\mathrm{pH}$ of a $0.050 \mathrm{M} \mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}$ solution. The $K_{u}$ value for $\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}$ is $1.4 \times 10^{-5}$
Calculate the $\mathrm{pH}$ of a $0.050-M \mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}$ solution. The $K_{\mathrm{a}}$ value for $\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}$ is $1.4 \times 10^{-5} .$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD