Question
Calculate the $\mathrm{pH}$ of a $0.42 \mathrm{M} \mathrm{NH}_{4} \mathrm{Cl}$ solution. $\left(K_{\mathrm{b}} \text { for ammonia }=\right.$ $\left.1.8 \times 10^{-5} .\right)$
Step 1
This makes $\mathrm{NH}_{4} \mathrm{Cl}$ an acidic salt. Show more…
Show all steps
Your feedback will help us improve your experience
Ahmed Ali and 95 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Calculate the $\mathrm{pH}$ of a $0.42 \mathrm{M} \mathrm{NH}_{4} \mathrm{Cl}$ solution.
Calculate the $\mathrm{pH}$ of a $0.36 \mathrm{M} \mathrm{CH}_{3} \mathrm{COONa}$ solution. $(K_{\mathrm{a}}$ for acetic acid $=1.8 \times 10^{-5} .$
Calculate the $\mathrm{pH}$ of an aqueous solution of $1.0 \mathrm{M}$ ammonium formate assuming complete dissociation. (p $K_{a}$ of formic acid $=3.8$ and $\mathrm{p} K_{b}$ of ammonia $=4.8$.)
Equilibrium
Topic 2 : Ionic Equilibrium
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD