Question
Calculate the $\mathrm{pH}$ of a solution prepared by adding $10.0 \mathrm{~g}$ sodium benzoate to $100 \mathrm{~mL}$ of $0.10 \mathrm{M} \mathrm{KOH}$.
Step 1
First, we need to find the moles of sodium benzoate and KOH in the solution. Sodium benzoate (C7H5NaO2) has a molar mass of 144 g/mol. So, 10.0 g of sodium benzoate is: (10.0 g) / (144 g/mol) = 0.0694 mol Since we have 100 mL of 0.10 M KOH, we have: (0.10 mol/L) Show more…
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