00:01
In answering this question, what we can do here is to first of all look at nh3 that dissolves in solution reversibly to form nh4 positive ions and or h negative ions.
00:15
Now looking at the initial concentration this is equal to 7 .1 and before the reaction takes place we won't be having any of these ions in solution.
00:23
Now looking at the change in the concentrations due to the dissolution process if ammonia decreases by x it means the ammonium iron will increase by x and the hydroxide ions in solution will also increase by x since they are in the ratio of 1 is to 1.
00:39
So what this means is at equilibrium we've got 0 .1 minus x of ammonia we've got x of ammonium and we've got x of the hydroxide ions.
00:48
And if we are to use the kb expression, this is going to be the concentration of ammonium multiplied by that of the hydroxide divided by that of ammonia.
00:59
Now if we are to use the kb expression, this is going to be the concentration of ammonia, if we are determining the kb, these concentrations right here are evaluated at equilibrium and we've just determined those concentrations.
01:07
And this is going to be x multiplied by x divided by 0 .1 minus x.
01:13
Now looking at the kb of ammonia, it is 0 .8, 1 .8 by 10 to the power negative 5.
01:19
And if we solve for x right here, we'll get an x that is equal to 1 .3 by 10 to the power negative 3 which is the concentration of the oh ions that are in solution at equilibrium...