00:01
Looking at the first part of this question, we have k -n -o -3 that is going to form k -positive and n -o -2 negative ions.
00:08
This is actually k -n -o -2.
00:11
And this n -o -2, it is going to react or dissolve in h -2 or producing h -n -o2 and the oh -n negative ions.
00:21
Now, if we are looking at the initial concentrations, this is going to be 0 .25.
00:26
And before the ionization process takes place, we won't be having any of these in solution.
00:32
Now looking at the change in the concentrations due to the dissolution process, if this decreases by x, this will increase by x and this will increase by x, since they are in the ratios of 1 is to 1.
00:43
So what this means is an equilibrium we've got 0 .25 minus x.
00:47
We've got x.
00:49
Now, if we are to use the kb expression, we've got kb being equal to the concentration of hno2, multiplied by that of the oh divided by the concentration of n or negative.
01:01
And these concentrations are evaluated at equilibrium, which we've just determined in the above step.
01:07
So this kb is equal to x multiplied by x divided by 0 .25 minus x.
01:13
And this should be equal to the kb, which is equal to kw divided by ka.
01:19
And this is equal to 10 to the negative 1 4 divided by 1 point...