00:01
Looking at the first part of this question, we've been reacting hf with sodium hydroxide to produce naf and h2o.
00:13
Now, if we look at the initial moles, we are looking at 3 millimals, 3 milamoles of the sodium hydroxide.
00:21
And if this decreases by 3, this will also decrease by 3, while this increases by 3.
00:31
They are in the ratios of 1 is to 1.
00:35
So the final moles we're looking at 0, we're looking at 0.
00:39
And right here we are looking at 3.
00:43
So looking at this, we then have this sodium f that is going to dissolve into solution, naf, dissolving into solution to produce n -a -o -h and hf.
00:58
So looking at this, if we are looking at an initial concentration, that is going to be equal to 3 would have a change that is negative y.
01:10
It means this will increase by y while this increases by y.
01:15
So at equilibrium we are looking at 3 minus y.
01:19
And here we are looking at y and y.
01:22
So recall that we've got our kb, which is going to be equal to the concentration of the hf multiplied by that of sodium hydroxide.
01:33
Divided by the concentration of sodium fluoride.
01:37
And these are concentrations at equilibrium that we've already determined, and we know the kp to be 5 .6 by 10 to the power negative 10...