00:01
So this problem, we're looking at the decay of a mulan into an electron and two neutrinos, an anti -electron neutrino and a milan neutrino.
00:12
I want you to find the maximum kinetic energy of the electron, so that's referring to a particular scenario.
00:20
The milan is at rest, and the neutrinos are in the opposite, their momentum is the opposite direction, is the electron momentum.
00:35
So in this case, we can have to find the q value.
00:42
Q is equal to the kinetic energies of the products.
00:49
This could be re -expressed as 105 .7 minus 0 .5 .1 .1.
01:03
Latrino rest masses are either zero or approximately zero.
01:07
So c squared it cancels out.
01:16
Q ends up equalling 105.
01:26
It's approximately 105 .2, roughly.
01:40
So then, what's the scenario we're dealing in? so conservation of energy, sorry, conservation momentum.
01:52
So we have like an electron going like this.
01:58
Like neutrinos going like that.
02:15
So what we're looking for is the electron momentum plus neutrino momentum equals zero.
02:37
The total momentum of the system is zero because the milan was at rest when it decayed.
02:47
So we're looking for p of the electron.
03:09
Okay.
03:09
So then it follows that the connect energy of the electron is p .c squared plus 0 .511 m .e .v squared minus 0 .511 m .e .v.
03:42
So the anti -electron neutrino, individually, that's p subscript of the neutrino.
03:58
So, and same thing with the moon on neutrino...