Problem

The concentration of glucose, $\mathrm{C}_{6} \ma…

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Problem 39 Hard Difficulty

Calculate the molality of each of the following solutions:
(a) 0.710 kg of sodium carbonate (washing soda), Na_ $\mathrm{CO}_{3},$ in 10.0 $\mathrm{kg}$ of waturated solution at $0^{\circ} \mathrm{C}$
(b) 125 $\mathrm{g}$ of $\mathrm{NH}_{4} \mathrm{NO}_{3}$ in 275 $\mathrm{g}$ of water-a mixture used to make an instant ice pack
(c) 25 $\mathrm{g}$ of $\mathrm{Cl}_{2}$ in 125 $\mathrm{g}$ of dichloromethane, $\mathrm{CH}_{2} \mathrm{Cl}_{2}$
(d) 0.372 g of tetrahydropyridine, $C_{5} \mathrm{H}_{9} \mathrm{N},$ in 125 $\mathrm{g}$ of chloroform, CHCl_{3}

Answer

a. $6.70 \times 10^{-1} \mathrm{m}$
b. 5.67 $\mathrm{m}$
c. 2.8 $\mathrm{m}$
d. 0.0358 $\mathrm{m}$

Leth B.

November 26, 2020

Top Chemistry 102 Educators

Allea C.

University of Maryland - University College

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Video Transcript

to calculate morality. We simply need to know the moles of the solute and we need to know the kilograms of the solvent. So for the following solutions we need to convert the mass of the salyut into moles salute. And then we need to convert the mass, if not in kilograms of the solvent, into kilograms of solvent. The first solution is a .710 kg sodium carbonate solution in 10 kg of water. So we'll convert the .710 kg of the salyut sodium carbonate into g sodium carbonate by multiplying by a 1000 well, then convert the grams sodium carbonate into molds sodium carbonate by dividing by its molar mass 106 g per mole. And we'll get .6, I'm sorry, 6.698 moles of sodium carbonate. To calculate morality will take the moles of sodium carbonate 6.698. And divide by the kg of the solvent water which was provided at 12 kg. This gives us a morality of .6698, Or to just three significant figures .6 70 for part B. We have 100 and 25 g of ammonium nitrate. We'll convert the moles of ammonium nitrate. This, I'm sorry, will convert the grams ammonium nitrate. This being the salute into moles ammonium nitrate. To do that, we simply divide by the molar mass of ammonium nitrate 82.04 g per mole. I'm sorry, just 80.04 g per mole. This gives us 1.562 moles of ammonium nitrate. To calculate morality of this solution will take the moles of the solute that we calculated and divide by the kilograms of the solvent. In this case it is water. We have 275 g of water, which corresponds to .275 kg. Water. This gives us the morality of 5.68 Ammonium nitrate for part C. We have 25 g cl two. This is our SAlyut will convert the 25 g cl two into moles cl two By divided by the Molar Mass Cl two 70.9 g per mole. And we get .353 moles cl two. To calculate morality will take the Mold Cl two that we just calculated and divide by the mass of the solvent, die chloral methane. In kilograms We were given the mass in g 125 g 125 g corresponds to .125 kg. And we get a morality of 2.8 to mobile al cl two for part D. The salute is tetra hydro period. I mean we have .372 g of it. We can calculate the moles of tetra hydro paradigm by simply dividing by the molar mass tetra hydro period in 83.123 and we'll get moles of 447 times 10 to the negative three. To calculate morality, we take the molds that we just calculated divided by the kilograms of just the solvent. The solvent is chloroform. We have 100 and 25 g of it. This corresponds to 250.125 kg, and we get a morality Of .0358 Morale.

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