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Calculate the molar mass for each of the following:

a. $\mathrm{O}_{2}$

b. $\mathrm{KH}_{2} \mathrm{PO}_{4}$

c. $\mathrm{Fe}\left(\mathrm{ClO}_{4}\right)_{3}$

d. $\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}_{4}$

e. $\mathrm{Ga}_{2}\left(\mathrm{CO}_{3}\right)_{3}$

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Missouri State University

Numerade Educator

Numerade Educator

University of California, Davis

so we have to calculate the more masses. So for 02 that is two times 16 for the two oxygen. So that's very two grams for more. Pardon me, that's ah K H two p 04 So for K is 39 point horn plus each to two times 1.1 plus P, which is 30.97 plus four times 16 for the oxygen's. So that is 136.9 grams per mole. Part C f e c 00 for three. How guys. So for the clothes off for the irons we need 55.85 Close three CIO, three times 35.45 plus 12 times 16 for the oxygen's comes out to 300 and 54.2 grams. Criminal party See for H 804 So four times to appoint on one for the carbons plus eight times 1.1 for hydrogen is plus four times 16 for the oxygen's. So that's 1 20 0.12 grams per mole for party G A to C 033 Okay, GE has 69.7 to plus the three times to appoint a one for the carbons, plus nine times 16 for talks of James comes out to to 49.75 grams per mole.