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Problem 111 Hard Difficulty

Calculate the molar mass for each of the following substances.
a. adipic acid, $\mathrm{C}_{6} \mathrm{H}_{10} \mathrm{O}_{4}$
b. caffeine, $\mathrm{C}_{8} \mathrm{H}_{10} \mathrm{N}_{4} \mathrm{O}_{2}$
c. eicosane, $\mathrm{C}_{20} \mathrm{H}_{42}$
d. cyclohexanol, $\mathrm{C}_{6} \mathrm{H}_{11} \mathrm{OH}$
e. vinyl acetate, $\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{2}$
f. dextrose, $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$

Answer

A.146.1 $\mathrm{g}$
B.194.2 $\mathrm{g}$
C.282.5 $\mathrm{g}$
D.100.2 $\mathrm{g}$
E.86.09 $\mathrm{g}$
F.180.2 $\mathrm{g}$

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Video Transcript

All right. So here we have six compliments. Were just simply asked to find the molar mass. Right? So first off, we have a dip IQ asset. He's all over again. Compounds, by the way, because they have carbon and oxygen. So the way that we find the molar mass of these compounds is by summing up the molar mass of each individual atom one by one, right? Oh, they So I'm also want to do a lot of rounding so that this won't take too much of our time of. And the all of these figures on both the list are in units of Gramps promote. So first off, you have carbon, which is 12 but because we have six, um, carbon Adams and one what Look, you'll be must multiply this number by six. Next, we have, um, hydrogen because a mole a massive, basically one. But because there's 10 hydrogen atoms in one molecule of a depict acid, we must also point by 10 and oxygen has a moment of 16. And with the same reasoning, we must multiply it. Mullah Mass by four. Yeah, and if we at all of this up, then we get 146 0.14 if you would have included the decimals. So yeah, that's basically the flow. Next off, we have caffeine. When that keeps us going, Case I'm gonna make a similar table where all the numbers are in units of grams per mole. We have carbon, hydrogen, nitrogen and oxygen. King, as we can see, we have eight, um, carbon atoms, Um, 10 hydrogen atoms. My surgeon has a moment of basically 14 and we have four hydrogen atoms. And for carbon oxygen, we have to Adams of it. And we're model of caffeine. And then as soon as we, uh, all of this up, we get 194.2 grams per mole. Next off we have I believe it's pronounced like a scene, which is a very large all cane. You've learned that yet? It is a very large number. I mean, very large molecule, not too large, but quite large. We have just carbon and hydrogen, so you can see we have 20 carbon atoms and then 42 hydrogen atoms. Because mullah masses one, I'm basically in the multiplying one by 42. Get a slant, give us a mullah Mass of 282 grams per mole Tip. Next, we have cycle Hexen All which is a cyclic alcohol, if that make sense. Everything years and the ends against From all you have Corbyn hydrogen and oxygen. This oh, age. Right. Here's on hydroxy group, which makes you know this compound, um, alcohol, if that clarifies anything. Okay, So carpet has more massive 12th and BF six, um, carbon atoms. And here we have 11 plus one hydrogen atoms and only one oxygen atom. It's going to close. Yeah, who? And if we just add all of these? Oh, it's a plus sign. We at a molar mass of Iran. Basically 100 norms. 100.2 grams per mole. Next, we have, um, vinyl acid Tate. Right. So I believe this is a plastic monomer. Uh huh. So, like a building block for what some plastics are made out of. So we have a carbon hydrogen and oxygen. Carbon is e, um, moments of 12. Well supplied by four. We have 600 ren's. And over here we have two oxygen's to oxygen's Teoh. Give us a some of 86 grams per mole for vinyl acetate. Lastly, we have sugar. It could be dextrose as the textbooks as a culture big look posted close will be fructose presenting a bunch of ice tumors. You've went that yet? And units grams per mole. We're going to list all of the molar masses. Okay, so we have six carbon atoms, 12 hydrogen atoms in six oxygen atoms. And that sums up to being 180 grams per mole for this sugar. So, um, shut up. And it appears that vile acetate is our monomer for rubbers, not plastic, but just declare for

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Top Chemistry 101 Educators
Stephanie C.

University of Central Florida

Nadia L.

Rice University

Allea C.

University of Maryland - University College

Morgan S.

University of Kentucky