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Problem 19 Medium Difficulty

Calculate the molar mass for each of the following substances.
a. sodium nitride, $\mathrm{Na}_{3} \mathrm{N}$
b. carbon disulfide, $\mathrm{CS}_{2}$
c. ammonium bromide, $\mathrm{NH}_{4} \mathrm{Br}$
d. ethyl alcohol, C_ $\mathrm{H}_{5} \mathrm{OH}$
e. sulfurous acid, $\mathrm{H}_{2} \mathrm{SO}_{3}$
f. sulfuric acid, $\mathrm{H}_{2} \mathrm{SO}_{4}$

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Video Transcript

in this problem were asked to calculate the molar mass for each given substance. Our first substances sodium mag tried so we can start by taking the molar mass of sodium. And if we look at our molecule, we see that sodium is represented three times in our molecule, so we won't apply the molar mass of sodium by three and then it once again, looking at our compound, we see that we only have one nitrogen represented in our molecule. So we'll just add the molar mass of our matric it. When we do our multiplication and add up or numbers, we find that the molar mass is equal to 82 0.98 grams per mole for our next compound, carbon die sulfide. We have one carbon represented in her compound, and we can see that we have to sulphur representative compounds, so we'll multiply the molar mass of sulfur bite. So our total molar mass of this compound is equal to 76.14 grams per mole. Our next compound is ammonium bromide, and we can see that we have one nitrogen in our compound, and it is out that we have four hydrogen in our compound. So we're going to multiply the molar mass of hydrogen by four. And then we have one room, bro mean represented in our compound. So we'll just add the mole and last there. So the molar mass of this compound is equal to 97 0.94 grams formal. Our next compound is ethyl alcohol. So we see that we have to carbons in our compound. So we're going to multiply that by our Miller massive carbon by two. And then we can add up all of the hydrogen that we see appearing in the compound. So we have six hydrogen total. It's a little. Multiply the molar mass of hydrogen by six and then finally, we just have one oxygen in our compound. So we'll add the Miller massive oxygen we find their molar mass is equal to 46.7 grams per mole. In part, you were dealing with sulphurous acid. So we can start by taking are more mass of our hydrogen and multiplying that by two. Since we have two hydrogen represented in our compound, we have one sulfur. So we'll just add the molar mass of sulfur to that number, and then we see that we have three oxygen, so we'll take our Mueller massive oxygen and multiply by three. So the overall more massive. This compound is equal to 82.8 grams per mole. Here in part F, we can recognize that sulfuric acid has one more oxygen than sulphurous acid. So instead of heading up all of our Miller masses again, we can just take the molar mass that we calculated for sulphurous acid and add the Mueller Ross of one oxygen as that's the only difference between these two molecules. So we do this, we find that the molar mass of sulfuric acid is equal to 98.8 grams per mole.