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Numerade Educator



Problem 9 Medium Difficulty

Calculate the molar mass of each of the following:
(a) $\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4} \quad(\mathrm{b}) \mathrm{CH}_{2} \mathrm{Cl}_{2} \quad$ (c) $\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O} \quad(\mathrm{d}) \mathrm{BrF}_{3}$


a) $\operatorname{Mr}\left(\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\right)=149 \mathrm{g} / \mathrm{mol}$
b) $\operatorname{Mr}\left(\mathrm{CH}_{2} \mathrm{Cl}_{2}\right)=84,91 \mathrm{g} / \mathrm{mol}$
c) $\mathrm{Mr}\left(\mathrm{CuSO}_{4} * 5 \mathrm{H}_{2} \mathrm{O}\right)=249,62 \mathrm{g} / \mathrm{mol}$
d) $\operatorname{Mr}\left(\mathrm{BrF}_{3}\right)=136,9 \mathrm{g} / \mathrm{mol}$


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Video Transcript

we have decoded the morning mass off four different compounds. So the 1st 1 would be ammonium phosphate. I'm only enforce fate. So we just need you found all the morning mass off each element, the lumber off each of them, and then we just add them together, and then we have to move the mask. So first a phobia. I'm only, um, among the Amis. Ah, um I say it's a multi Ryan's Leigh Anne four plus. And the way we look at their chemical formula Also hear about ah, can't go find one for here. We have free doing it. So I'm only a so for each arm, only a We have nitrogen. So the minimize the nitrogen 14 and then the mass of hygiene is one. So I have four times one over here of the we have free off the I'm only a So we have 23 more by battle over or ammonium um, mass. And then I'm going to add the mass from the mass Wolf falsely was very one. Oxygen will be 16 but we evolved as a 16 times for so where we just calculator richer people defined as one's ah, for nine grand for more for among the young phosphates. And then we move on. We have sage to see El. We have to. I corps me, Vinnie. So we have one chi pond surges corresponding to 12 while two hydrogen. So we have 111 times two, Um because hydrogen is to Sorry. I just want swept off them and they called me Will be a roughly 45. So we're 45 times two, and then we add them together we should be able to find an extra 84 Kuemper mo. Okay, so and then the next one we have ah, Cooper solve a panto. Hi Treat It just copped herself a link with 542 mark you. So, first of all, we just find out, um, more than massive copper. The mood of life's of corporations 63.55 million. Five from a testicle ourself for we'll be equals deferring to point. Ah 07 again. Get violent test book, and then we have four oxygen. So we have four times 16 each of our oxygen. We because friend of 16 and there were five water. Um, I would look at water as one whole unit. How so? For water, We have one arm, oxygen, and we have to Hodgins or I plus two times one. And I have modified the whole thing by five. So we have succeed. Sleep on 55 plus fear free. 2.7 past four times. 16 plus we times. Ah, Bracket 16. Thus, to all three times in 18. So we would have to 49.62 Emperor, move for them with a massive copper sulphate, Pender hydrate. And the last one we have Ah, ball for pro mean trifle. Right. So we have one grooming off. Romi will be cost more than 72. Foreign nine. Um, Grandpa Amo. And then you can find out from a test force. Well, and then Ah, for, um 4444 I, uh, you should be able find as around 19 point as well. So we just need to multiply after a full ride by three. And then plus the massive pro permanent, we should be able to find that the total mass is one knows