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University of Toronto

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Problem 11

Calculate the molar mass of each of the following:

$$\begin{array}{llll}{\text { (a) } \mathrm{N}_{2} \mathrm{O}_{4}} & {\text { (b) } \mathrm{C}_{4} \mathrm{H}_{9} \mathrm{OH}} & {\text { (c) } \mathrm{MgSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}} & {\text { (d) } \mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}}\end{array}$$

Answer

a) $\operatorname{Mr}\left(\mathrm{N}_{2} \mathrm{O}_{4}\right)=92,02 \mathrm{g} / \mathrm{mol}$

b) $\operatorname{Mr}\left(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{OH}\right)=74,04 \mathrm{g} / \mathrm{mol}$

c) $\mathrm{Mr}\left(\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{OH}\right)=246,38 \mathrm{g} / \mathrm{mol}$

d) $\operatorname{Mr}\left(\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}\right)=158,12 \mathrm{g} / \mathrm{mol}$

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## Discussion

## Video Transcript

So we have to calculate the mother mass off four defense. Ah, compound. So the first one's answer. Oh, for we just look for the, um, more than mass of individual elements. And then we add them together over. You have to move the mass often individual compounds. So for nitrogen issue off the army were 14 for Children with two times 14 and also jin were four times 16. So you goes in nine to gram per mo. Okay, so and then we have C for H 90 h. And I I think this is a beauty. No. So we have four. Um um, cabin So this week? Because we're into 12 times floor and there were 900. We have nice time one times for and that we're one Aussie gin and also Ah, we have one. Ah, hydrogen. So you just you can't just filed the corresponding more the mass of individual atom at them together. And then you should be able to have of arm roughly 74 of gram per mo. Okay. And then the second not the 3rd 1 would be medicine. Sophie. Ah, we have I agree. We've seven height high hide high trade between water. So yeah, again, we just found myself magnesium will be 24.31 and then sell for will be for the 2.7 and that you have four oxygen seven watermark you and then we're out Everything together. Just you have us 246.38 Kuemper mo And then for the last one, where calcium, we've Ah, if ah, I think it's Ah, it's ah, Molecular Ryan. But it's called half with the name, but it's a C two ex trio to, and we have to off them. So we just let you file the monuments of magnesium will be four d point. Um oh, wait. And then we just need to find her one units there, Muller marking the massive one. You did all that and then one by two. So we have their two cabins or two times. Ah, 12. And there were three. Ah, for hydrogen. And then we have two ostriches on trial for 16 times too. So we just at this number together, and then we should be able to, um But we find this number and I'm about to, and then we know the overall way forward from this and I. And they were just plus no at the calcium Boulder, Mass. And then just to be able to find his wife never on 158.0 eight's glam promote.

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$$\begin{array}{llll}{\text { (a) } \mathrm{SnO}} & {\text { (b) } \mathrm{BaF}_{2}} & {\text { (c) } \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}} & {\text { (d) } \mathrm{MnCl}_{2}}\end{array}$$

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