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Calculate the molar solubility of $\mathrm{CdCO}_{3}$ in a buffer solution containing 0.115 $\mathrm{M} \mathrm{Na}_{2} \mathrm{CO}_{3}$ and 0.120 $\mathrm{M}$$\mathrm{NaHCO}_{3}$

$4.52 \times 10^{-11} \mathrm{M}$

Chemistry 102

Chapter 15

Equilibria of Other Reaction Classes

Chemical Equilibrium

Carleton College

University of Maryland - University College

Lectures

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00:52

I run, This is Ricky. And today we're working on problem one of one, and we're gonna be solving for the Moler solid ability of cagney and carbonates In a buffer containing 0.115 moles of C three minus two in point went to a molder of H E av three minutes and we're getting a K A value of seven point, then seven times 10 to the negative 11. All right, so we have to solve four each plus concentration X, and we can do that using Henderson. Possible. So P H is equal to p K plus long of CEO three minus two over H C 03 minus. No. And let us rearrange this in terms of, um, hydrogen concentration. Remember, P H is equal to the negative log each plus, So I'm just gonna be doing some quick algebra. So negative log. Each plus equals P K. Let's log CEO three minus two over. It's you HC, hopefully minus H plus. Concentration is equal to 10 raised to be negative p. K A plus log sea of three minus two h c. O for the minus. And this is all in the exponents and remember K a r p k vicious team. Negative log of K. So we get 10 point 15 we get a hydrogen concentration. Oh, 7.3 times 10 being negative. 11 Moeller when we feel everything in Yep. And all right, so now we can go here. It's okay. A was equal to H plus C 03 minus two h c 03 minus. We've solved for this. We were given this and you're also given this, so we just have to solve for carbonate 0.115 Moeller. All right, so now that we have carbonate concentration, we can use this to calculate the Moler Sally ability of cadmium carbonate. So seedy c 03 associate into CD plus two. We'll see you three minus two A s P is equal to 5.2 times since the naked 12. All right? And so we already have an initial concentration of 0.115 more carbonate. So plus x And then this would just be X ke sp is equal to cadmium carbonate concentrations we want to solve for the cabinet and concentration and then put everything in and see this kind of awkward because we have this X but we can A soon X is negligible and we can do this because Ke sp is so small. That was probably very little association that occurs and we get that academy and concentration is 4.52 times 10 to the negative 11th which is on orders and orders of magnitude less and 100.115 So matter and this is the more sell the ability. So if this video is helpful, I will see you in the next one.

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