We do this by dividing the mass of the solute by its molar mass.
For (a), the molar mass of $\mathrm{H}_{3} \mathrm{AsO}_{4}$ is 141.9 g/mol. So, the number of moles of $\mathrm{H}_{3} \mathrm{AsO}_{4}$ is $\frac{27.8 \mathrm{~g}}{141.9 \mathrm{~g/mol}}$.
For
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