00:01
This question is to calculate the molarity of each of the following solutions.
00:04
The first solution is 0 .195 grams of cholesterol in 0 .10 liters of solution.
00:15
So in order to calculate the malarity, we need to know the mole and also the volume.
00:28
Given the mass, we can determine the mole by dividing the mass by the molar mass, and finally divide everything by the volume to get the molarity.
00:48
So for this solution in part a, the malarity is determined by taking the mass, which is 0 .195 grams, dividing by the molar mass of cholesterol.
01:04
So you have to compute the molar mass of cholesterol here.
01:10
And when i competed that molar mass, i attained a value of 386.
01:21
0 .661 grams per mole.
01:28
We end up dividing by the volume which you've been given as 0 .1 .0 liters.
01:35
So this when solved gives a similarity of 5 .04 times times times times of power minus 3 molar of cholesterol.
01:53
In part b, we do the same thing.
01:57
Similar approach.
01:59
So our molarity is going to be attained by rewridden the mole by the volume solution, given the mass or mole is going to be the mass, divided by the molar mass of ammonia.
02:18
The molar mass of ammonia is 17 .031...