00:02
Okay, in this problem, we want to determine the molarity of each of these solutions that we have here.
00:09
So let's look at the first one.
00:11
The first one is we have 100 milliliters.
00:16
In order to determine the molarity of the solution, we need to convert those milliliters to liters.
00:21
So we do that by doing 100 milliliters, and to convert that to liters, we have one liter over 1 ,000 milliliters, which gives us 0 .1 liters of solution.
00:36
And we were given the number of moles in this one.
00:40
So we have 0 .6, sorry, 0 .56 moles of parium chloride.
00:45
So how do we determine the molarity? we divide the number of moles by the liters, the volume that we have.
00:53
So we take the 0 .56 moles of barium chloride, and we divide it by 0 .1 liters, which gives us 5 .6 v -a -c -l -2.
01:11
Now let's circle this.
01:15
Let's move on to the next one.
01:19
So for the next one, we have 200 mils.
01:21
So, again, we need to convert to liters, which gives us 0 .2 liters.
01:34
And we were given the number of moles.
01:38
In this case of sodium carbonates, we have 0 .1...