00:01
So in our first example, we have some sodium nitrate.
00:07
That's going to break into sodium ion and nitrate ion.
00:14
And since the sodium nitrate was 0 .25 molar, the concentration of the sodium ion is going to be 0 .25 molar.
00:26
And the concentration of the nitrate is also going to be 0 .25 molar.
00:33
Because that compound completely dissociates.
00:38
In our second compound, we've got magnesium sulfate, and we're forming mg2 plus and s .o4 -2 -minus.
00:50
Again, we're going to start with 0 .01 -3 -molar, and it's going to completely dissociate, so it's going to give me 0 .01 -3 -molar m -g -2 -plus and 0 .013 -molar s -4 -2 -1.
01:09
In the third example, we've got c6h1206.
01:16
This is a molecular compound, so it's not going to dissociate at all, so its concentration is simply what it was given, 0 .015 molar glucose.
01:34
Now we're going to take a couple solutions and combine them, so they're going to get diluted.
01:38
So we're going to look at this dilution formula.
01:45
So the new molarity, once it's diluted, will be its original molarity times v1 over v2, where v2 equals the total volume of the two solutions...