00:02
Hello everyone, we are going to understand this question here given in the question mass density linear mass density of rod it is represented by lambda which is equal to a into s let s is equal to x so we can write lambda is equal to a into x so let there is a small part d x so let the partial length of rod is d x partial length of rod is equal to d x so mass of partial length mass of partial length dm is equal to lambda into d x mass linear mass density into length of rod linear mass density is a into x into d x now calculating a center of mass of rod so let center of mass of rod is represented by x c o m which is equal to integration of dm into x upon integration of dm.
01:40
Here value of dm is a x into d x upon upon dm is equal to a x into d x.
01:59
Here we forgot to multiply by x now doing further calculation a x square x upon x x into d x x into d x now after calculation we will get x q upon 3 upon x squared upon 2 here integration limit is from 0 to l now doing further calculation we will get l q upon 3 whole upon l square upon 2 after calculation we will get 2 l 3.
02:55
This is the center of mass of rod.
03:00
Now calculating the movement of inertia of rod, d -i is equal to d -m into x square.
03:11
Not x because we have taken dm from the one end.
03:18
So here we can take r square.
03:22
Now r is equal to distance from center of mass is equal to 2l upon 3.
03:31
Minus x.
03:33
So we can write d i is equal to d m into 2l upon 3 minus x square.
03:44
But here r is along to rod but we have to find the perpendicular distance from the axis of rotation.
03:55
So we can take it a square but here a is equal to let's see the diagram.
04:16
This is the length r this length is r and we have to find the a.
04:25
Now in triangle we can see this angle is alpha then this one is also alpha.
04:35
This is r and this is a...