00:02
Hello everyone we are going to understand this question here given in the question in the question there is given a diagram in which there is a rod having mass m and length l mass of uniform rod mass of uniform rod is equal to m and length is equal to l and it is making alpha angle with axis of rotation let's take a small length.
00:58
So from here, mass of uniform rod is m and length is given l.
01:02
So mass density of rod, mass density of rod, mass density of rod is equal to m upon l.
01:21
Let dx is a partial length.
01:25
Let dx is partial length from one end at distance x.
01:55
So, mass of partial length, mass of partial length, dm is equal to mass density m upon l into d x.
02:14
So taking the movement of inertia about the given axis, so di is equal to m upon l, means dm into, dm into perpendicular distance between point of rotation.
02:37
Rotational axis into perpendicular distance of partial length of rod about the axis of rotation.
02:51
That is, if this length is l, then this dotted line length will be x -sign theta, x -sign alpha.
03:04
X -sign alpha...