Question
Calculate the normality of a solution of sodium carbonate if a 25.0 -mL sample requires 39.8 mL of 0.405 N sulfuric acid in a titration.
Step 1
We do this by dividing the volume in milliliters by 1000. \[39.8 \, \text{mL} \, \text{H}_2\text{SO}_4 \times \frac{1 \, \text{L}}{1000 \, \text{mL}} = 0.0398 \, \text{L} \, \text{H}_2\text{SO}_4\] Show more…
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