Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

Calculate the number of cations and anions in each of the following compounds: (a) $0.764\ \mathrm{g}$ of $\mathrm{CsI}$, (b) $72.8 \mathrm{g}$ of $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7},(\mathrm{c}) 6.54 \mathrm{g}$ of $\mathrm{Hg}_{2}\left(\mathrm{NO}_{3}\right)_{2}$

a. $1.73 \cdot 10^{21} \mathrm{Cs}$ cations$1.73 \cdot 10^{21} \mathrm{I}$ anionsb. $$\begin{aligned}&2.975 \cdot 10^{23} \mathrm{K} \text { anions }\\&1.487 \cdot 10^{23} \mathrm{Cr}_{2} \mathrm{O}_{7} \text { anions }\end{aligned}$$c. $$\begin{array}{l}2.975 \cdot 10^{23} \mathrm{Hg} \text { anions } \\1.487 \cdot 10^{23} \mathrm{NO}_{3} \text { anions }\end{array}$$

Chemistry 101

Chapter 3

Mass Relationships in Chemical Reactions

Chemical reactions and Stoichiometry

University of Kentucky

Brown University

University of Toronto

Lectures

04:02

A chemical reaction is a process that leads to the transformation of one set of chemical substances to another. Chemical reactions can be either spontaneous, requiring no input of energy, or non-spontaneous, typically following the input of some type of energy, such as heat, light or electricity. Chemical reactions are usually characterized by a chemical change, and they yield one or more products after the reaction is complete. Chemical reactions are described with chemical equations, which symbolically present the starting materials, end products, and sometimes intermediate products and reaction conditions. Chemical reactions happen at a characteristic reaction rate at a given temperature and chemical concentration. Typically, reaction rates increase with increasing temperature because there is more thermal energy available to reach the activation energy necessary for breaking bonds between atoms.

08:02

In chemistry, a combination reaction is a chemical reaction in which two or more reactants combine to form more than one product. In a decomposition reaction, one reactant splits into two or more products.

10:00

Calculate the number of ca…

02:41

Determine the ionic charge…

07:17

For each of the following …

03:04

Determine the number of ea…

01:21

Write the name for each of…

00:36

03:28

Identify and name the cati…

For part, a given information is the mass ofsesium. Iodide is mass of sesiumidideis equal to 0.746 gramhere. We have to calculate to kilcuate the number of kate, ions and aninesso. First find the number of moles of frst find the number of moles of sesiumidide c s. Ithe molar mass of mass of sesumyditeis molar mass of cesium iodide is equal to molar. Mass of sterium plus molar mass of iodine is equal to molar. Mass of cism is 132.905 gram per mole, plus molar mass of iodine is 126.90 gram. 9904 gram per mole is equal to 259.808 gram per molethe, number of moles of cesemiodide is moles, cesium iodide is temanite, is number of moles of cesium. Iodide is equal to given mass of cesium iodide divided by molar. Mass of cesium iodide is equal to 0.746 gram. Given my sucsamiodide and 259.808 gram per mole is the molar mass of cesium iodide is equal to 2.87 into 10 raised to the power minus 3 mole gram encelvithgrown, so 1 mole of cesium iodide contains 1 mole of cesium. Therefore, the number of moles of cesium is 2.87 into 10, raise to the power minus 3 moles 1 mole of c i did contained 1 mole fiend. Therefore, the number of moles of iodine is also 2.87 into 10, raised to the power minus 3 mole. So, according to, according to gogar number 1 mole contains, according to bogdo's number 1 mole contains 6.022 multiply 10 raised to the power 22 molecules. Now we will find the number of hit ions, ccm and anines iodine. The number of gatine is number of cations is equal to a number of moles of cesium into woe. Got rosh number is equal to 2.87 into 10, raise to the power minus 3 moles into 6.022. Multiply 10 raised to the power 2323 kate. Irons per mole is equal to 1.73 into 10 raised to the power 21 cesium cition peand, the number of anine isis equal to a number of moles of iodine into gadros number is equal to 2.87 into 10, raise to the power minus 3 mole into 6.022 into 10, raise to the power 23 anions per mole is equal to 1.73 into 10, raised to the power 21 iodine and ionsso. The result is 1.73 into 10, raise to the power 21 cesium ketines and 1.73 into 10, raised to the power 21 iodine aninesand. Given information for part b, the mass of k, 2 c r, 2, o 7 is mass of k, 2 c r. 2. O 7 is equal to 2.8 gram. We have to find the number of gateionsand anionesand. First, you will find the number of moles of k. 2 c r, 2, o 7, the molar mass k, 2 c l 2, o 7, is is equal to 22 into molar mass of potassium plus 2 into molar. Mass of chromium plus 7 into molar. Mass of oxygen is equal to 2 into molar. Mass of potassium is 39.098 gram per mole plus 2 into molar. Mass of chromium is 51.996 gram per mole plus 7 into molar. Mass of oxygen is 15.999. Gram per mole is equal to 294.181 gram per molethe number of moles of moles of k, 2 c r. 2, o 7 is number of moles of k, 2 c r. 2. O 7 is equal to mass of k, 2 c r, 2 o 7 divided by molar mass of k, 2 c l 2, o 7, is equal to given mass of a 2 o 7. Is 2072.8 gram divided by molar? Mass is 294.181 gram per mole is equal to 0.247 moles 1 mole of k. 2 co. 2 zo 7 contains 2 moles of k. Therefore, the number of moles of k is 2.2 into 0.247. Mole is equal to 0.494 moles and 1 mole of k to c r 2. O 7 contains 1 mole of c r, 2. O 7 point. Therefore, the number of moles of c r 2 o 7 is 0.274. So, according to evegarow's number 1 mole contains 6.02 to multiply 10 raised to the power 23 molecule. Now we will find the numbers of find the numbers of katine, kidiones and andinesso. The number of gatinsk into the vogarose number is equal to 0.494 moles of potassium into vegetous number 6.02. To multiply 10 raised to the power 23 ketines per mole is equal to 2.975 multiply 10 raised to the power 23 potassium kate ions, and the number of an in is an ions, as is equal to number of moles of c r 207 into able rows numbers Equal to 0.247 into 6.022 multiplied 10 raised to the power 23 in irons per mole, is equal to 1.487 multiplied 10, raise to the power 23 c r, 2, o 7 in irons. So the result is 2.975 into 10, raise to the power 23 potassium cations and 1.487 .10 raised to the power into 10 days or 23 c r, 2, o 7 nions and given information for part c, the mass of a j 2 no 3 whole twice is Mass of key to n o 2 n o 3 voltige is equal to 6.54 gram and we have to calculate the number of ketinesketynes of mercury and anines nitrate. First, we will find the number of moles of 8 g 2 n o 3 whole twicethe. Molar mass of e g, 2 n o 3 whole twice is molar. Mass of is equal to 2 into molar mass of g plus 2 into molar. Mass of nitrogen plus 3 into molar. Mass of oxygen is equal to 2 into molar. Mass of mercury is 201.590 gram per mole plus 2 into molar. Mass of nitrogen is 14.007 gram per mole plus 3 into molar. Mass of oxygen is 15.99 gram per mole is equal to 525.188 gram per molethe number of moles of is in g 23. Whole twice is equal to given mass of the compound divided by molar. Mass of the compound is equal to given mass is 6.54 gram divided by molar. Mass is 524.188 gram per mole is equal to 1.25 multiplied and raised to the power minus 2 moleand. Here is 1 mole of h. G 2, n o 3 whole twice contains 2 moles of g. Therefore, the number of moles of hg is 2 into 1.25 multiplied. 10 raised to the power minus 2. Mole is equal to 2.50, is equal to 2 into 1.2 5.10. Raise to the power minus 2 mole is equal 2.50 moles 50 into 10, raised to the power minus 2 mole and 1 mole of 8 g 2 no 3 whole twice contained 2 moles of n o 3. Therefore, the number of moles of n o 3 is also also 2.50 multiplied. 10 raised to the power minus 2 moles. So, given information for part caccording to vogarde's number 1 mole contains 6.022 multiplied and raised to the power 22 molecules. Now we will find the number of find the number of keitions g and aninesn o 3. The number of kations is equal to a number of moles of g into abogado number, so the number of moles of mercury is 2.50 multiply. 10 raised to the power minus 2 mole into bogardos number is 6.022 multiplied. 10 raised to the power 23 katine per mole. Is equal to 1.51 multiplied 10 raised to the power 228 g cations, the numbers of of anynes is equal to number of moles of n o 3 into avogados number is equal to 2.5010, raise to the power minus 2 mole into 6.02 to multiply 10 raised to The power 23 aninesper mole is equal to 1.51, multiply 10 raised to the power 22, no 3, andirons so 2.975 into 10, raised to the power 23238 g, ketones and 1.4877 into 10, raised to the power 23 n o 3, a nines.

View More Answers From This Book

Find Another Textbook

Numerade Educator

06:00

Calculate the energies needed to remove an electron from the $n=1$ state and…

01:11

Predict the atomic number and ground-state electron configuration of the nex…

06:23

A student is given four solid samples labeled $\mathrm{W}$ $X$. $Y$, and $Z$…

00:51

After operating a Daniell cell (see Figure 18.1 ) for a few minutes, a stude…

01:09

Little is known of the chemistry of astatine, the last member of Group 7 A. …

07:32

A flask with a volume of 14.5 L contains 1.25 moles of helium gas. Estimate …

08:35

Calculate the percent composition by mass of all the elements in calcium pho…

00:55

Why is it dangerous to add water to a concentrated acid such as sulfuric aci…

05:14

A $44.0$ -$\mathrm{g}$ sample of an unknown metal at $99.0^{\circ} \mathrm{C…

16:41

Draw Lewis structures for the following organic molecules: (a) methanol $\le…