Calculate the number of grams of cobalt that contain the same number of atoms as 2.24 g of iron.
So here we have 2.24 grams of iron, and we're to find how much this would weigh this particular quantity would away if we just watch the atoms of iron into the pool balls. So what do we know? So what we know now is that the the Adams in this quantity must equal the Adams of cobalt. That's these assumption. So how do we find items? So the conclusion for Adams this soft number of items z just malls multiplied, but of a cultures number. Mm. And that's an a forgotten number. And we know that, um, malls is equivalent to mass over molar mass, and we'll still keep the ever guardrails constant. Remember here. Great. So So they lied. So we're looking out for the massive cobalt. I just am see massive foot boat who in this quantity of iron. So here we have a Here's the amount of moles or Adams of Cobalts President in this formula. So you know, we stay that a number of Adams is the same. So we'll just said Thies equal to each other because that's what we're stating. That Adams Cobalt is equal toe Adams of ire because um, mass over molar, as times are large. Number is Adams. So yes, F for iron, See for cobalt. So now let's hope the red birds. Yeah. So what can we cancel? Oh, we should get rid of an A Because so in both thoughts, the numerator, it's negligible. And if we want to solve just from C, we will just multiply both sides by the molar mass of cobalt so that we have it as this. The massive iron multiplied by the molar mass of cobalt divided by some old, a massive iron. Again, it's equivalent to massacre boat so and makes it very straight for to plague in numbers. At the beginning, we had 2.24 grams of iron. And then let's just look at our periodic table to find the mole. Massive cobalt. So here it says, basically 58 ma. Include as Mel's two month right. But you should okay, over the molar mass of iron, which is 55 55 points 845 grams per mole. So yeah, boom. That will equal to 2.36 Gramps. Kobal. Yeah, eso You just took the mass of iron. I multiplied it by you know, this factor of molar mass