00:02
Okay, so here we have a thousand grams of zirconium.
00:07
And we are trying to find how much would this weigh if we replace their zirconium atoms with lithium? so same number of atoms in like both cases, but how much would it weigh if we just swapped out the zirconium atoms for lithium atoms? okay, so the given here is same number of atoms.
00:32
Okay.
00:36
So what is our equation for a number of atoms? so it's moles multiplied by avagagos constant, n -a.
00:57
So we're working with mass here.
00:59
We're looking for a mass and we're given a mass.
01:01
So let's see what do we know about moles? we know that moles is equivalent to mass over molar mass.
01:10
And we'll just keep avagatra's constant right there where it was.
01:16
All we did was substitute out moles for math over mole on us because, you know, it's equivalent.
01:23
All right.
01:24
So here we have our equation that will help us.
01:29
So we know that the number of atoms of zirconium equal that of lithium.
01:37
So we're looking for mass of lithium.
01:41
So let's do ml for massive lithium, and ml again, capital ml for molar mass of lithium.
01:54
And this constant is equivalent to the mass of zirconium over the molar mass of zirconium times avogadro's constant...