00:01
Okay, so here we have five grams of tellurium, and we are trying to find the mass of mercury that would be in this quantity of telaryum.
00:12
So if we were to just switch out, take this quantity, and switch out the telarium atoms for mercury atoms.
00:21
So we're just going to take this weight and multiply it by like a molar mass factor.
00:29
But let me show you how we get to that.
00:34
All right.
00:35
So what we are going to state, what is a given here is that atoms of tellerium are equivalent to the atoms of mercury.
00:57
The number of atoms is equal to moles times avagagos.
01:08
And that moles is equivalent to mass over molar mass.
01:15
So then if we just substitute, we get mass multiplied by avatogadish number divided by molar mass is equivalent to atoms.
01:24
And i just said that atoms of tellerium equal atoms of mercury.
01:28
So let's write that up.
01:32
So i'm going to say tellurium is t and mercury is h.
01:47
So here we have massive tellurium divided by molar massive telarium times avagagos constant multiplied by massive mercury no is equivalent sorry to massive mercury divided by a molar massive mercury times avagagos constant atoms and these two atoms equal each other.
02:15
Yeah so right off the back to what can we cancel out.
02:20
You can get rid of n .a...