00:03
In this question, we have to calculate the oxidation number for sulfur in the following polyatomic ions.
00:13
The first one is so3 to minus.
00:18
Now, oxidation number of sulfur plus three times oxidation number of sulfur of 3 is equal to minus 2.
00:33
Because that's the charge of this so3.
00:37
Now oxidation number of sulfur we have to calculate.
00:42
Therefore, oxidation number sulfur plus three times oxidation number of oxygen is minus 2.
00:51
So we are multiplying 3 with minus 2 is equal to minus 2.
00:56
Therefore, oxidation number of sulfur is minus 2 and plus 6.
01:05
That is, oxidation number of sulfur is plus 4 in so3 to minus.
01:15
Now, the next ion is h .s .o .4 minus.
01:22
So let's write oxidation number of hydrogen plus oxidation number of sulfur plus four times oxidation number of oxygen.
01:37
And this ion has minus one charge, so it will be equals one.
01:43
Oxidation number of hydrogen is one plus oxidation number of sulfur plus four times oxidation.
01:52
Number of oxygen is minus 2...