00:06
We're asked to find the value of a surface integral.
00:16
So we're told that n is the outer unit normal, away from the origin of the parabolic shell, s with equation 4x squared plus y plus z squared equals 4, where y is greater than are equal to 0.
00:33
And we're given a vector field f, which is negative z plus 1 over 2 plus x, x i plus the inverse tangent of y j plus x plus 1 over 4 plus z k and rastifying the surface integral over s of the gradient crossed with f so the curl of f dotted with n first let's compute the curl of f from the description given well again this is the gradient crossed with f and so this is going to be zero i minus 2j plus 0k.
01:56
And we were given the equation of the surface, f of x, y, z equals 4x squared plus y plus c squared.
02:19
And so from this we have that the gradient of little f is equal to, see, we have 8xi plus 1j plus 1j plus 2 .0 .0 .0 .5.
02:40
Z, k, and we have that our normal vector, n, in particular it's the normal away from the origin...