00:04
Here we have to find the percent composition by mass of all the elements in ca3, po4, hall 2.
00:53
First we will find the molar mass of the compound, molar mass of c .a .3 .p .o .4, whole 2 is equal to 3 into molar mass of calcium plus 2 into molar mass of phosphorus plus 2 into plus 8 into molar mass of oxygen is equal to 3 into molar mass of calcium is 40 .07 8 gram per mole plus 2 molar mass of first first is 30 .974 gram per mole plus 8 into molar mass of oxygen is 15 .99 gram per mole is equal to 310 .174 gram per mole is the calculated molar mass of c.
02:49
3 u4 whole 2 now we can find the percent by mass of all the elements so percent by mass of calcium is equal to 3 into molar mass of calcium divided by molar mass of the compound in 200 percent is equal to 3 into 40 .078 gram per mole divided by 310 .174 gram per mole into 100 % is equal to 38 .76 .76 % percent by mass of calciumium present in the comparison.
04:34
Is 38 .76%.
04:44
And next is percent of phosphorus is equal to 2 into molar mass of phosphorus divided by molar mass of the compound, ca3, p .o4, whole 2, into 100 percent is equal to 2 into molar mass of phosphorus is equal to 2 30 .974 gram per mole divided by 310 .174 gram per more into 100 % is equal to 41 .277%.
05:55
And next is percent of oxygen is equal to 3 .3 into more.
06:09
Molar mass of oxygen divided by molar mass of the compound ca3o4, hold twice into 100 % is equal to 3 into 1 .008 gram per mole divided by molar mass of the compound is 310 .174 gram per mole divided by molar mass of the compound is 310 .174 gram per mole...