00:01
Okay, so for this question, they want us to find the present composition of all of the elements in each of the compounds.
00:07
So let's do na2 -s -4 first.
00:11
So the molecular weight of na2 -s -o -4 is 142 .04 grams per mole.
00:20
Now let's find the present composition of sodium first.
00:24
So we have one element, one mole of sodium is equal to 23 grams.
00:31
And one more of sulfur is 32 grams and one mole of oxygen is 16 grams right so the present composition of sodium is 23 grams times it by 2 since we have 2 sodiums divided by the total mass of the compound which is 142 .04 this gives us 23 times 2 is 46 divided by 142 .04 and we get 32 .36%.
01:14
32 .36%.
01:17
Now for sulfur, we have 32 grams divided by 142 .04, we get 22 .53%.
01:33
And for oxygen, we have 16 grams.
01:37
There is 4 oxygens.
01:41
Divided by 142 .04 and we get 45 .58%.
02:00
Now for the next one, we have n204.
02:04
The molecular weight of n204 is 92 grams per mole.
02:14
Nitrogen is 14 grams per mole, oxygen is 16 grams per mole.
02:24
So we have nitrogen is 14 grams times it by 2 since we have two we have 2nd by 92 grams and we get 30 .43 % of nitrogen...