00:01
In this problem we're going to discuss gravity and gravitational forces.
00:08
And the gravitational force exerted from an object with mass m1 on an object m2, a distance r away, can be written as f g for gravity equals large g, which is a gravitational constant, times m1 m1 times m2 over the distance squared and g here is a gravitational constant with the value of now approximately sorry 6 .67 10 to the power of minus 11 newton meter squared over kilogram squared, squared.
01:15
Okay, and let's now consider that we have a person, this is earth, earth, now we have a person who's in sacramento, which is at sea level, and also on top of mount everest.
01:43
So let's make this dot here and dot here.
01:47
And what we now want to do is to compare the weight, or which also the gravitational force between these two places.
01:58
So we will have f, the gravitational force at sacramento, and the gravitational force on mount everest.
02:13
And what we know is that at sacramento, we are at sea level, so r here we would say r1 equals to re.
02:27
Which is there we'll take that to be the radius of the earth and on mount everest we'll have r2 which is equal to the radius of the earth plus 8 ,800 meters now we will use the equation up here this one to approximate the difference in weight between sacramento and mount everest.
03:09
So what we want to do is we want to calculate fg sacramento over fg mount everest.
03:37
Now we'll see that this is g.
03:46
M of earth times mass of the person.
03:56
Over r .e.
04:01
Squared over...