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Problem 121 Hard Difficulty

Calculate the pH of a $2.00 \mathrm{M} \mathrm{NH}_{4} \mathrm{CN}$ solution.

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Video Transcript

Here's a tough problem. Let me just give you the information. All we have to do is calculate the pH of a 2.0 bowler solution of ammonium cyanide. And this problem is indeed a little tougher than you might first think. When I say calculate, pH got several things we need to do here. First, we're going to have to split this reaction into the NH four plus the ammonium and the C n. And then I'm just gonna for lack of a better term, call those parts. Then we're going to have to find the K for one of, um, one of the reactions and the K B for the K B for the other reaction. Once we have those, um, we're going to have to figure out like which one is going to be used up so we'll say which is in excess and by how much. Then after that, we're gonna have to find the pH. So that's our plan for this ones. But the reaction into the ammonium on the Sinai parts fine k find K B K for one of, um, KB for the other one. Then we'll do another little equation to see like, we'll get two answers here, and we'll figure out which one will run out of which one will be an access. The one that's in excess and by how much of in excess will be used to find pH. Okay, let's begin. Doesn't really make any difference which part you start with. But I think I'll parts start with the ammonia so ammonium and we'll just leave this one in black NH four, which with a plus one charge with water, is going to be an equilibrium with, um, NH three. That's ammonium. Let me get rid that little mark there and hide rhodium. Now that one really isn't too hard here to figure out because I said we're going to split this up. We have ammonium, and that obviously has this and this. So this I'm going to make a little note is an acid. This is my conjugal base. My sea bass. This is my base, and this is my conjugal asset. Okay, I'm gonna go back to my previous page after we have that. Then we're going to find the K B, and I'm going to do that whole thing for this problem. Okay? So we're going to do now is we're gonna have our ice table. And if you recall, we were given it the beginning that we have 2.0 Moeller. We ignore this, so I'm just gonna put a line through this. We have zero and zero. Those air initial concentrations. The concentration of these will increase by X, giving me equilibrium. Concentrations of X. This will decrease and concentration by act. So I get 2.0 minus X Now my goal here is to solve for X.

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Watch More Solved Questions in Chapter 15

Video Transcript

Raymond Chang, Kenneth A. Goldsby

Chemistry

Theodore Donnell

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Stephen Pulliam

Jake Rempel

This textbook answer is only visible when subscribed! Please subscribe to view the answer

Chemistry

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Raymond Chang, Kenneth A. GoldsbyChemistry

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