00:01
So we're asked to find essentially the ph values of three different acidic solutions.
00:06
So our first acidic solution has a concentration initial of one molar and a pca of 4 .76.
00:21
So a weak acid has the general equation of form at ha yields h plus plus a minus.
00:29
So it's essentially as a concentration of 1 .7.
00:32
Molar, but some of that dissociates.
00:37
So we can write our equation in the form ka equals the concentration h plus times a minus over ha.
00:46
So this becomes x squared over 1 minus x.
00:53
And so we're going to try to make the approximation that the dissociation is not significant.
00:59
So x is much less than 1 molar.
01:02
And then basically we can rewrite this as 1 .0.
01:09
And this becomes the square root of 10 to the negative 4 .76, which yields that x is equivalent to 0 .004 molars.
01:27
So the concentration of h plus equals this quantity here.
01:36
And basically we can check our approximation by finding that essentially our approximation is satisfied.
01:44
So the concentration h plus is here, and ph is the negative log of the concentration.
01:53
So we can find that essentially the ph in this case is equivalent to about 2 .398, and we have to pay attention to significant figures.
02:07
Since for acids and bases, significant figures are basically after the logged digit are considered significant.
02:16
And we have a second solution of the form, basically, we have methylamine.
02:23
So protonated methyl amine is essentially this compound.
02:45
So we can essentially find that protonated methylamine can dissociate into methylamine and a free hydro, a free proton...