00:01
In this question, we've been asked to determine the pressure in atmosphere using both the ideal gas law and the finderwals equation.
00:07
So looking at the ideal gas law, pv is equal to nrt.
00:11
So p is equal to nrt divided by the volume.
00:15
So if we are to use an r of 0 .08 -206 atmosphere, liters, per, mole, kelvin, it means this temperature should be in kelvin and the volume should be in liters.
00:27
And this pressure is going to be reported in atmosphere.
00:31
So if we are to make the substitutions, we have p being equal to 1 .55, multiplied by 0 .08206, multiplied by the temperature, which should be in kelvin, 530 degrees celsius plus 273 gives us 803, and we divide this by the volume, which is 3 .23 liters...