The formula for the reduced mass is given by $\mu = \frac{m_1 m_2}{m_1 + m_2}$, where $m_1$ and $m_2$ are the masses of the two atoms.
In this case, $m_1$ is the mass of deuterium (D) and $m_2$ is the mass of chlorine-35 (Cl-35). The atomic masses of deuterium
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