00:01
Calculate the resonant frequency for each of the circuits.
00:09
For the first circuit, the impedance will be equal to 1 by j omega c, that is the capacitance, is in parallel with the resistance and the inductance which are in series.
00:25
Therefore we can write it as r plus j omega l by j omega c whole divided by r plus j omega l plus 1 by, j omega c.
00:37
Simplifying further the impedance comes out to be r plus j omega l by 1 minus omega square l c plus j omega r c this can further be written as r plus j omega l into 1 minus omega square l c minus j omega r c divided by 1 minus omega l c whole square plus omega square r square c square.
01:08
Now at resonance, the imaginary part of impedance will be equals to zero.
01:15
Therefore, zero equals omega -not l into 1 minus omega -not square lc minus omega -not r -square -c.
01:28
Then from here the value for omega -not comes out to be square root of l -minus r -square -c by l -square -c.
01:37
This can be further simplified to 1 by lc minus r square by l square...