00:01
This question we are asked to determine solubility of a lead hydroxide.
00:07
First, in water.
00:08
So we're given the ksp or solubility product constant for it as 1 .2 times 10 to the negative 15.
00:16
We need to figure out what the solubility is, and so we're going to set up an ice table.
00:24
I represents the initial concentrations of the components here.
00:30
Now lead hydroxide is a solid, so it's not going to be part of the equilibrium expression as solids and liquids are never part of an equilibrium expression, but rather it's these two product ions that are going to figure in here.
00:43
Initially, before any solubility is taking place, we don't have any of either of those two ions.
00:50
Over time, we're going to produce x amount of the lead ions, but 2x amount of the hydroxides, because look at the coefficient here.
01:01
Twice as many hydroxides are produced for every one mole of lead ion that's produced.
01:07
To find the equilibrium concentrations then of those two ions, we simply add together the i and c lines here.
01:13
0 plus x is an x concentration for the lead ion.
01:18
0 plus 2x gives me an equilibrium concentration of 2x for the hydroxide.
01:24
And now let's go back to the solubility product expression and set it up.
01:32
So the ksp value again that was given to us is 1 .2 times 10 to the negative 15...