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Calculate the standard enthalpy change for the reaction $$2 \mathrm{Al}(s)+\mathrm{Fe}_{2} \mathrm{O}_{3}(s) \longrightarrow 2 \mathrm{Fe}(s)+\mathrm{Al}_{2} \mathrm{O}_{3}(s)$$sgiven that $$\begin{array}{c}2 \mathrm{Al}(s)+\frac{3}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{Al}_{2} \mathrm{O}_{3}(s) \\\Delta H_{\mathrm{rxn}}^{\circ}=-1669.8 \mathrm{kJ} / \mathrm{mol} \\2 \mathrm{Fe}(s)+\frac{3}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{Fe}_{2} \mathrm{O}_{3}(s) \\\Delta H_{\mathrm{rxn}}^{\circ}=-822.2 \mathrm{kJ} / \mathrm{mol} \end{array}$$

$-847.6 \mathrm{kJ} / \mathrm{mol}$

Chemistry 101

Chapter 6

Thermochemistry

Carleton College

University of Kentucky

University of Toronto

Lectures

05:27

In chemistry, a chemical reaction is a process that leads to the transformation of one set of chemical substances to another. Both reactants and products are involved in the chemical reactions.

06:42

In chemistry, energy is what is required to bring about a chemical reaction. The total energy of a system is the sum of the potential energy of its constituent particles and the kinetic energy of these particles. Chemical energy, also called bond energy, is the potential energy stored in the chemical bonds of a substance. Chemical energy is released when a bond is broken during chemical reactions.

01:59

Calculate the standard ent…

01:52

02:02

Use the following themoche…

03:08

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So for this question, were supposed to find the heat of this reaction. Given that we have two other chemical equations and we know they're heats of reactions, it's the two chemical reactions that you know are the following. The heat of this reaction is negative. 1669.2. Killer jewels for more and second chemical reaction that we have is fault in the heat of this reaction is negative. 800 22.2 Killer jewels promote So what skin? When solving these kinds of problems, it's very important to write out all the equations that you could identify more ratios and see which chemicals and compounds you to be on the left side versus the right side. The first thing that we want to find is this first reactive, just two moles of aluminum metal, the only equation that has two moles of aluminum metal or any moles of aluminum. It'll that matter very 1st 1 and it's already on the left side like you on the decide equation, and there's already two moles. So this equation remains unchanged, and that's the final equation that we're gonna need for the 1st 1 Now for the 2nd 1 we want to find F E two or three or iron oxide, and we see that the only iron oxide in both these equations is right here now, while there's one mole, which is what we want, the problem is it's on the products, not the reactions. And so to correct for that you want to multiple display negative one. Now I know that even though I may not look at Iron or the ale 203 that's on the right side that this must be the answer, and these must be the final equations, because those were the only two conditions that satisfy the reactions. But just to quickly verify, we can also see that this workout the two FB when you want to apply by negative one will show up on the right side, and the ale two or three is already there. And in this case, these two oxygen's will cancel out because this one move, the 2nd 1 who moved to the right side wants multiply by negative one. Now all we need to do add up the to Dr H is that we saw. So we added negative 1000 669.8, and we subtract that with negative 222.2. And that will yield a final answer of negative 847.6 killed Jules for more, and that is the final answer.

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