00:01
We are given two reactions, and we are asked to solve for the delta h of the other reaction.
00:06
So this is just a traditional hess's law calculation.
00:09
The two reactions that are given to us are two moles of s -o -2, plus o2 going to two moles of s -o -3, delta h negative 196, a fourth of a mole of s -8 solid, plus three moles of o2, going to two moles of s -o -3.
00:27
Delta h is negative 790 kilojoules.
00:30
If we reverse the first reaction and multiply it by one half, which is what is necessary in order for us to get s .o .2 as a product.
00:45
And in the target reaction, we need s .o .2 as a product, so that's why we need to reverse it.
00:50
We then divide it by two because we only need one mole of s .o .2.
00:55
And we are starting out with two moles of s .o .2.
00:59
So we'll reverse it, multiply it by 1 .2...