Calculate the standard free energy change for the reaction,
$$
\mathrm{N}_{2(\mathrm{~g})}+3 \mathrm{H}_{2(\mathrm{~g})} \longrightarrow 2 \mathrm{NH}_{3(\mathrm{~g})} \text { at } 298 \mathrm{~K}
$$
Given $\Delta H^{\circ}=-92.4 \mathrm{~kJ}$ and $\Delta S^{\circ}=-198.3 \mathrm{JK}^{-1} .$ Also, comment on the
result.