00:01
For this problem, we are asked to calculate the second and third order polynomials for the given function f of x equals x squared plus 1 over x plus 1, the value a equals negative 2.
00:12
So to begin, we want to take our first derivative here.
00:16
F prime of x, to do that, we will have to apply the quotient rule.
00:21
So we'll have derivative of x squared plus 1 times x plus 1.
00:25
So we have 2x times x plus 1, minus derivative of x plus 1 times x squared plus 1.
00:31
So that's just going to be minus x squared minus 1 in the numerator.
00:36
And then we divide by x plus 1 squared.
00:39
Should be able to simplify that down to x squared plus 2x minus 1 divided by x plus 1.
00:47
Oops, x plus 1 all squared.
00:50
Then our second derivative is again going to require the use of the quotient rule here.
00:57
I'm going to be simplifying this down off screen.
01:00
The result of taking the second derivative there...