00:01
So in this problem, we want to calculate the theoretical air fuel ratio on a mass and a mole basis for the combustion of ethanol, which is c2h50h.
00:15
And so the, i should use a single arrow there for regular chemistry location.
00:27
So the, let's see here, the chemical reaction, the reaction here is the ethanol plus air.
00:36
Again, and that's for one oxygen molecule, we have about 3 .76 nitrogen molecules.
00:46
And so we have this ratio here that we need to find how much air we need.
00:51
And we're going to get out of here with some co2, some h2, some h2, and some nitrogen.
00:56
And we don't know how much.
00:58
Those are a, b, and c.
01:00
So we need to equate, you know, we need to make sure we conserve atoms, essentially.
01:06
So for carbon atoms, we have two of them over here, and we have a of them over here.
01:13
So that means a has to be two.
01:16
For hydrogen atoms, we have five, six of them over here, and we have two b of them over here...