The reaction is given as:
$$
\mathrm{Cu}(s)+\mathrm{Cl}_{2}(g) \rightarrow \mathrm{CuCl}_{2}(s)
$$
The change in moles is calculated as the difference between the number of moles of products and reactants. In this case, we have 1 mole of CuCl2 produced and 1 mole
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