The oxidation half-reaction at the anode is:
$$
\mathrm{Cu}(s) \rightarrow \mathrm{Cu}^{2+}(a q)+2 e^{-}
$$
The reduction half-reaction at the cathode is:
$$
\mathrm{Ag}^{+}(a q)+e^{-} \rightarrow \mathrm{Ag}(s)
$$
To balance the electrons, we multiply the
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