The flow rate is given as \(2 \, \text{L/min}\).
Since \(1 \, \text{L} = 0.001 \, \text{m}^3\) and \(1 \, \text{min} = 60 \, \text{s}\),
\[ Q = 2 \, \text{L/min} \times \frac{0.001 \, \text{m}^3}{1 \, \text{L}} \times \frac{1 \, \text{min}}{60 \, \text{s}} =
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