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Calculate the volume in $\mathrm{mL}$ of a $1.420 \mathrm{M} \mathrm{NaOH}$ solution required to titrate the following solutions:(a) $25.00 \mathrm{mL}$ of a $2.430 \mathrm{M} \mathrm{HCl}$ solution(b) $25.00 \mathrm{mL}$ of a $4.500 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$ solution(c) $25.00 \mathrm{mL}$ of a $1.500 \mathrm{M} \mathrm{H}_{3} \mathrm{PO}_{4}$ solution

(a) $42.78 \mathrm{mL} \mathrm{NaOH}$ solution is required(b) $158.45 \mathrm{mL}$ NaOH solution is required(c) $79.22 \mathrm{mL} \mathrm{NaOH}$ solution is required

Chemistry 102

Chapter 4

Reactions in Aqueous Solutions

Solutions

Aqueous Equilibria

Carleton College

Rice University

Brown University

Lectures

03:58

In chemistry, a solution is a homogeneous mixture composed of two or more substances. The term "solution" is also used to refer to the resultant mixture. The solution is usually a fluid. The particles of a solute are dispersed or dissolved in the solvent. The resulting solution is also called the solvent. The solvent is the continuous phase.

00:41

In chemistry, an ion is an atom or molecule that has a non-zero net electric charge. The name was coined by John Dalton for ions in 1808, and later expanded to include molecules in 1834.

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Calculate the volume in mi…

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Determine the volume, in m…

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Calculate the volume, in m…

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Determine the final volume…

Okay, question 91 in question 91 required to find a volume of solum hydro sal with the non concentration. So now this idea it the formula m e n over v and from this equation we do many times i now to day. We want to find equal for this equation: v equals n over n and how we can do it. We have to find more of the sodium hydroxide, because sodium hydroxide concentration already won all 4 to 0. In the way we can inifithe concentration of sodium hydroxide we'll have to fight from the right amenthequation. So before we do it, we have to hide the number of hydrochloric passifihow. Can we do it that building of a volume of volume of hydrochloric acid and now we have to find a mohydrochloric acid and is equal to pi, p? 3, so this is for p, o 675 more after we find a ma. We have the the equation to find a radiometer more at on from the equation we get 1 and 1. I have to walstein more ratio, and now, if i have a 6 or 75 s here, we got at 1 in a certain hydroxide should be the same, and now we get the columhydroxide. So we can find a volume from the question at this gave her. I out of 27 a liter and if we convert to meta 42 power 78, keep in mind, you have to keep the pace now we got to be they see in a white although, but we have to try a question which hydrosulphuric acid symphoriand now from question. Be the mosasticon now coolin should prove it as i i o 25 later time for the concentration 54500, and so what we will have. We have the more of saturation 11 rufin mo, and then we write a question. We balance this equation. We form a calculated more, do we know to me and now we get to 1125, so there should be 2 tame, 11135 point and this equals .225 and from this oxyhydroxide now we have to see see see we have how many more the said, 25 days of Phosphoric acid and the concentration, the concentration 1.500 l for fricasie, we calculate a more obstrictis pi, o 375. More and now we have to write a equation to further onathan. They follow. We find a high rate o. We have to compel this equation. First now we see 1 radio here 13 point so now for cocodri acid, that 2 or 375 point. So this should be 3 times this equal poi, 11 joule 5. And now we get the magothydroxide. We can the baltimore hydroxide for c for blonde over concentration. Now we're done so, you have told you have to view this formula fussily for m equal over v, so we'll get a result: v, equal n n. So if you see concentration molarity to relay to this equation right away at this equation right away- and here is the comparatum.

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