Calculate the volume of $\mathrm{H}_{2}(\mathrm{g}),$ measured at $26^{\circ} \mathrm{C}$ and 751 Torr, required to react with $28.5 \mathrm{LCO}(\mathrm{g}),$ measured at $0^{\circ} \mathrm{C}$ and 760 Torr, in this reaction.
$$3 \mathrm{CO}(\mathrm{g})+7 \mathrm{H}_{2}(\mathrm{g}) \longrightarrow \mathrm{C}_{3} \mathrm{H}_{8}(\mathrm{g})+3 \mathrm{H}_{2} \mathrm{O}(1)$$