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Calculate the wavelength of light that produces its first minimum at an angle of $36.9^{\circ}$ when falling on a single slit of width 1.00$\mu {m}$ .

$\lambda=600 \mathrm{nm}$

Physics 103

Chapter 27

Wave Optics

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for a first order minimum. We have empty city call too one. Then we can write. The Lambda is equal. D'oh! The slipped were That is a d times a sign off that divided by am So m is one. So I would leave it like that then the Devi have is one micro meeting that is a quick 10 to the power minus six meters majors substituting the angle we have year he's 36.9, 36.9. Then simplifying this expression gives us the Lambda off 600 nano meters.

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