0:00
Hello.
00:01
Today we'll be talking about chapter 12, question 86, which asks us to calculate the pressure of gases in a couple of different scenarios.
00:11
So let's look at the first scenario where we have 1 .3 moles of gas.
00:20
We have volume is equal to 8 .0 liters.
00:25
Temperature is equal to 293 kelvin.
00:29
And lastly, we have, of course, the ideal gas constant.
00:32
Which is equal to 0 .08206 liter atmospheres per mole kelvin.
00:42
And so if we set up our ideal gas law, pv equals nrt, we want to solve for the pressure.
00:51
We can do this by moving the volume to the other side of the equation to give us p equals nrt over v.
01:01
And then plugging all the numbers in, 1 .3 moles times.
01:06
R, the gas constant, times 293 kelvin, divided by 8 .0 liters, gives us the pressure in atmospheres of 3 .91 atmospheres of gas.
01:25
And so, we can use this same approach with pretty much any numbers, any conditions that we're given...