00:01
In this exercise, we are told that calls arrive according to a poisson process at a rate of 20 per minute.
00:09
For part a, we were asked, what is the mean time until the 100th call? so if x is the time until the 100th call, and the calls arrive according to a poisson process, then x has an erlang distribution with rate of 20, and r is equal to 100.
00:45
For an erlang distribution, the expected value is equal to r over lamb, which is 5.
01:01
For part b, we are asked for the meantime between call numbers 50 and 80.
01:06
Now, because of the memoryless feature of an erlang distribution, the expected time between the 50th and 80th call calls is the same as the expected time until the 30th call.
01:44
And the time until the 30th call is an erlang with rate equal to 20 per minute and r equals equals 30.
02:07
So that expected time is equal to 30 over 20 or 1 .5...