00:01
This question covers the cleavage of ethers by hydrohalyde acids, specifically hf.
00:12
And what we can remember from the text is that other halide acids such as hydrobiotic and hydrobaromic acid, our very strong acids are very capable of cleaving ethers.
00:30
So these guys can cleave ethers.
00:31
To relate the rest of the halide series back to these two, we need to understand what makes these such good ether cleavers.
00:47
And the best way to explain this is we have an ether, this dimethyl ether.
00:56
In order to cleave this ether, we have to have two things happen.
00:59
One, we need to protonate it.
01:00
And then two, there has to be some sort of substitution reaction happening that allows this either to be cleaved into.
01:08
So let's take h .i as our example.
01:11
So if we have h .i.
01:17
If we say, for example, this reaction happens first because hydrolyotic acid is a very strong acid, then we would form an intermediate where we have this iodide ion plus a protonated ether, which because of that formal charge on the oxygen has been activated towards, has been activated towards substitution.
01:48
And the reason why this reaction can happen is because iodide is a very, very large ion.
01:53
You have to think all the way down, you know, if we think of our halides here, we have fluorine at the top, then we have clbr, and then i down here.
02:07
Right.
02:07
I, you know, we know that atomic size increases as we go down the periodic table.
02:14
So iodide is very large.
02:16
Because it's so large, so bulky, that makes it an excellent nucleophile because those electrons have ample access to the substrate they're trying to attack.
02:24
As a result, we would see a reaction like this, wherein iodide would attack the ether, and we would have the formation of methyl iodide.
02:38
And that would be the cleavage of this either...